8. A psychologist assigned twenty rats to a drug or no drug group amount of time
ID: 3325240 • Letter: 8
Question
8. A psychologist assigned twenty rats to a drug or no drug group amount of time with which they sol learn a red light predicte delivered on the left was recorded. The rats receiving the d task, with SD- 10. The rats receiving no drug took an average of 105 seconds SD = 15, Did the drug likely improve performance? a. Yes, because those taking the drug b. Yes, because the mean difference is not zero. c. No, because the standard deviations are different. d. No, because there is too much overlap between the groups. e. No, because there is less variability in the drug group f. Maybe, but a post-hoc test needs to be conducted to detect the no drug gr to evaluate how a drug affects the ve a discrimination task. The number of seconds that it took a rat to d food delivered on the right side of an experimental chamber and water was rug took an average of 120 seconds to learn the scored higher than those not taking the drug. than detect a difference g groupExplanation / Answer
8.
Given that,
mean(x)=120
standard deviation , 1 =10
number(n1)=20
y(mean)=105
standard deviation, 2 =15
number(n2)=20
null, Ho: u1 = u2
alternate, H1: 1 > u2
level of significance, = 0.05
from standard normal table,right tailed z /2 =1.645
since our test is right-tailed
reject Ho, if zo > 1.645
we use test statistic (z) = (x-y)/sqrt(s.d1^2/n1)+(s.d2^2/n2)
zo=120-105/sqrt((100/20)+(225/20))
zo =3.721
| zo | =3.721
critical value
the value of |z | at los 0.05% is 1.645
we got |zo | =3.721 & | z | =1.645
make decision
hence value of | zo | > | z | and here we reject Ho
p-value: right tail -Ha : ( p > 3.721 ) = 0.0001
hence value of p0.05 > 0.0001,here we reject Ho
ANSWERS
---------------
null, Ho: u1 =u2
alternate, H1: 1 > u2
test statistic: 3.721
critical value: 1.645
decision: reject Ho
p-value: 0.0001
Yes,
we have enough evidence to support the claim that those taking drug scored higher than those not taking drug
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