Can anyone offer some help on this question? To investigate the efficacy of a di
ID: 332542 • Letter: C
Question
Can anyone offer some help on this question?
To investigate the efficacy of a diet, a random sample of 16 male patients is drawn from a population of adult males using the diet. The weight of each individual in the sample is taken at the start of the diet and at a medical follow-up 4 weeks later. Assuming that the population of differences in weight before versus after the diet follow a normal distribu-tion, the t-test for related samples can be used to determine if there was a significant de-crease in the mean weight during this period. Suppose the mean decrease in weights over all 16 subjects in the study is 3.0 pounds with the standard deviation of differences com-puted as 6.0 pounds. 6. 7. 8. The t-test should be The computed 't' statistic is There are -tailed degrees of freedom for this test. 9. The critical value (CV ) for a one-tailed test of the null hypothesis of no difference at the ? 0.05 level of significance is A one-tailed test of the null hypothesis of no difference would 10. ( be rejected / not be rejected ) at the ?-0.05 level of significance 11. If we were interested in testing againstExplanation / Answer
1. the t test should be _______-tailed.
one
Reason:- As the sample is normal distributed thus test should be one tailed
2. the computed t statistic is _______.
T statistic = sample mean / [standard deviation/sample size0.5 ]
T statistics =3/6/160.5=3/1.5 = 2.00
3. there are _______ degrees of freedom for this test.
Degree of freedom = sample size -1 = 16-1 =15
4. the critical value for a one-tailed test of the null hypothesis of no difference at the a = 0.05 level of significance is _______.
From the table of critical value for a one-tailed test , level of significance will be 1.7531
5. a one-tailed test of the null hypothesis of no difference would _______ (be rejected/not be rejected) at the a = 0.05 level of significance.
be rejected
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