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10.)If 41% of people have blood type o, what is the probability that none of thr

ID: 3326014 • Letter: 1

Question

10.)If 41% of people have blood type o, what is the probability that none of three randomly selected students will have blood type 0? 59 a. 59.0% (. 20.5%) c.348% d, 41.0% 11.,) Randomly choose one of the 225 people in a certain organization. What is the conditional probability the person chosen is a women given that you Men who smoke -40 Women who smoke 25 65 chose a smoker? Men who don't spoke - 70 Women who don't smoke 90 160 a. 25/115 b.1-401 10/C25/65 d. 90/160 12..) Which is greater, A the conditional probability a person speaks Spanish given the person is Mexican or B the conditional probability a person is Mexican given the person speaks Spanish? a. Ab. B c.equal d. not enough information 13..) On examining a large number of college essays researchers found this: Number of spelling errors in a paper 1 2 3 45 Probability of this man spelling errors .09.19 21 37 .11 .03 The first quartile of the data set consisting of the numbers of spelling errors in the essays is a.) 1 error b. two errors c. 3 errors d. 4 errors. 2-S 14. How many ways are there to choose 3 books out of 8 books on a shelf? a. 336. b. 56. c. 83. d. 3 15. If 40% of people have a certain antibody in their blood, what is the probability that 2 of 4 randomly selected people will have this antibody? a.4. .42e .62.

Explanation / Answer

Ans:

10)Probability of not having blood type O=1-0.41=0.59

P(none of the three have blood type O)=0.59^3=0.2054

20.5%

11)

P(women/smoke)=P(women and smoker)/P(smoker)=(25/225)/(65/225)=25/65

13)First quartile means that 25% of the data falls below that

0.9+0.19=0.28 approximatey makes first quartile,so 1 error

14)8C3=(8*7*6/3*2*1)=56

15)Binomial distribution:

n=4,p=0.4

P(x=2)=4C2*0.42*(1-0.4)2=6*0.42*0.62

smoke dont smoke total men 40 70 110 women 25 90 115 total 65 160 225
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