Give a conclusion for the confidenceinterval test.14 points A researcher wants t

Question

Give a conclusion for the confidenceinterval test.14 points A researcher wants to test the claim that, on average, more juveniles than adults are classi- fied as missing persons. Records for the last 5 years were recorded as follows: Juveniles: 65513 65934 64213 61914 59167 Adults: 31364 34478 36937 35946 38209 2. Test the claim at 0.05 level of significance. Teststatistis t = State the null and alternative hypothesis. State your conclusion for your hypothesis test. 4 points 4 points 3.A new insectercide is advertized to kill more than 95% of roaches on contact. a. Is this sufficient evidence to support ther manufacturer's claim of 95%. The insectercide was applied to 400 roaches. Only 384 died immediately after contact. b. Find a 95% confidence interval for the true proportion of roaches killed on contact. Test statistic Pp and Confidence Interval pt ze Use = 0.05 Level of significance. pa Tm p-Po po (1-Po) State the null and alternative hypothesis State your conclusion for your hypothesis test Give the 95% Confidence Interval 4 points points 4 points 4 points Give a conclusion for the confidence interval test. BCDEF G 2! TT, H I J K L M N P PQ RS TU TEXAS INSTRUMENTS

Explanation / Answer

Q2.
Given that,
mean(x)=63348.2
standard deviation , s.d1=2813.3593
number(n1)=5
y(mean)=35386.8
standard deviation, s.d2 =2631.0395
number(n2)=5
null, Ho: u1 = u2
alternate, H1: u1 > u2
level of significance, = 0.05
from standard normal table,right tailed t /2 =2.132
since our test is right-tailed
reject Ho, if to > 2.132
we use test statistic (t) = (x-y)/sqrt(s.d1^2/n1)+(s.d2^2/n2)
to =63348.2-35386.8/sqrt((7914990.5509/5)+(6922368.85056/5))
to =16.2318
| to | =16.2318
critical value
the value of |t | with min (n1-1, n2-1) i.e 4 d.f is 2.132
we got |to| = 16.23176 & | t | = 2.132
make decision
hence value of | to | > | t | and here we reject Ho
p-value:right tail - Ha : ( p > 16.2318 ) = 0.00004
hence value of p0.05 > 0.00004,here we reject Ho
ANSWERS
---------------
null, Ho: u1 = u2
alternate, H1: u1 > u2
test statistic: 16.2318
critical value: 2.132
decision: reject Ho
p-value: 0.00004
have evidence to support more juvillions than adults

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