What is the test statistic? z=____ (Round to two decimal places as needed.) What

Question

What is the test statistic?

z=____

(Round to two decimal places as needed.)

What is the P-value?

P-value=_____

(Round to four decimal places as needed.)

Score: 0.4 of 1 pt 14 of 35 (19 complete) HW Score: 45.5%, 15.93 of 35 pts & 8.3.19-T Question Help In a study of 420,110 cell phone users, 116 subjects developed cancer of the brain or nervous system. Test the claim of a somewhat common belief that such cancers are affected by cell phone use. That is, test the claim that cell phone users develop cancer ofthe brain or nervous system at a rate that is different from the rate of 0.0340% for people who do not use cell phones. Because this issue has such great importance, use a 0.001 significance level. Identify the null hypothesis, alternative hypothesis, test statistic, P-value, conclusion about the null hypothesis, and final conclusion that addresses the original claim. Use the P-value methood and the normal distribution as an approximation to the binomial distribution. Which of the following is the hypothesis test to be conducted? OB. Ho: p0.00034 H1 : p 0.00034 Ho:p#000034 H: p 0.00034 Ho:p=0.00034 H: p> 0.00034. ° C. F. Ho: p 0.00034 H:p 0.00034 0 E. What is the test statistic? (Round to two decimal places as needed.)

Explanation / Answer

Solution:-

State the hypotheses. The first step is to state the null hypothesis and an alternative hypothesis.

Null hypothesis: P = 0.00034
Alternative hypothesis: P 0.00034

Note that these hypotheses constitute a two-tailed test. The null hypothesis will be rejected if the sample proportion is too big or if it is too small.

Formulate an analysis plan. For this analysis, the significance level is 0.001. The test method, shown in the next section, is a one-sample z-test.

Analyze sample data. Using sample data, we calculate the standard deviation () and compute the z-score test statistic (z).

= sqrt[ P * ( 1 - P ) / n ]

= 0.000028444
z = (p - P) /

z = - 2.25

where P is the hypothesized value of population proportion in the null hypothesis, p is the sample proportion, and n is the sample size.

Since we have a two-tailed test, the P-value is the probability that the z-score is less than - 2.25 or greater than 2.25.

Thus, the P-value = 0.0244

Interpret results. Since the P-value (0.0244) is greater than the significance level (0.001), we have to accept the null hypothesis.

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