171OnlineTest 3-Ch 4 X Lecture Power-points x.3 sampling Distribution i x-w 1710

Question

171OnlineTest 3-Ch 4 X Lecture Power-points x.3 sampling Distribution i x-w 1710 line-5Ch4) CO Not secure www.webassign.net/web/Student/Assignment Responses/last?dep 17589202 Suppose that you roll two fair dice. Give the following probabilities as fractions. What is the probability that you get a sum of 8? 3+5 4+4 2/ What is the probability that your first die is a 4? What is the probability that your first die is a 3 and you get a sum of 5? What is the probability that your first dies is a 3 or you get a sum of 52 What is the probability that the sum is not 5? Type here to search

Explanation / Answer

a) (2,6) (3,5) (4,4) (5,3) (6,2)= 5

P(sum 8)= 5 /36 = 0.138889

b)(4,10 (4,2) (4,3) (4,4) (4,5) (4,6)

P(first die is 4)= 6/36 = 0.16667

c) first die is 3 =6

sum is 5 = (1,4) (2,3) (3,2) (4,1)

P( first die is 3)=6/36 and P(sum is 5) = 4/36

P( First die is 3 and sum is 5): (3,2) =1/36 =0.02778

d)P( First die is 3 or sum is 5)= P(First die is 3) +P(Sum is 5) -P( First die is 5 and sum is 5)

P( First die is 3 or sum is 5)= 6/36+4/36-1/36 =9/36 =0.25

e) P(sum is not 5) =1-P(sum is 5)

P(Sum is 5)= 4/36 = 0.1111

P(Sum is not 5) =1- P( Sum is 5)= 1-0.1111=0.88889

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