QUESTION 7 A sample of N =161 is drawn from the US. population which has a mean

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QUESTION 7 A sample of N =161 is drawn from the US. population which has a mean income of $74,896 and a variance of 25 678, what will be the population mean of the sampling distribution of all the sample means? Answer accurate to two decimal places. QUESTION 8 In a new infographic from health website Evoke.le showing how much food residents of various countries eat per day, the U.S. trumps with 3,770 calories, followed closely by Austra with 3,760. Suppose the variance of the sampling distribution of the mean calories for samples of 98 students is 346. What will be the variance of the sampling distribution of the mean for 25 students? Answer nocurate to 4 decimal places. Click Save and Submit to save and submit. Click Save All Answers to save all ansvers Save All Answers Close Win : FI F3 FS F6 97 F8 19

Explanation / Answer

Solution7:

sampling distribution of sample mean=xbar=population mean

=74896

ANSWER:74896

Solution 8:

variance for 98 students=346

sigma^2/n=346

sigma^2/98=346

sigma^2=33908

variance of sampling distribution for 25 students is

=sigma^2/n=33908/25

=1356.32

ANSWER:1356.32

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