The National Student Loan Survey asked the student loan borrowers in their sampl

Question

The National Student Loan Survey asked the student loan borrowers in their sample about attitudes toward debt. Below are some of the questions they asked, with the percent who responded in a particular way. Assume that the sample size is 1298 for all these questions. Compute a 95% confidence interval for each of the questions, and write a short report about what student loan borrowers think about their debt. (Round your answers to three decimal places.)

(a) "To what extent do you feel burdened by your student loan payments?" 58% said they felt burdened. ,

(b) "If you could begin again, taking into account your current experience, what would you borrow?" 54.3% said they would borrow less. ,

(c) "Since leaving school, my education loans have not caused me more financial hardship than I had anticipated at the time I took out the loans." 33.6% disagreed. ,

(d) "Making loan payments is unpleasant but I know that the benefits of education loans are worth it." 59.9% agreed. ,

(e) "I am satisfied that the education I invested in with my student loan(s) was worth the investment for career opportunities." 59.2% agreed. ,

(f) "I am satisfied that the education I invested in with my student loan(s) was worth the investment for personal growth." 69% agreed. ,

Conclusion

While many feel that loans are a burden and wish they had borrowed less, a minority are satisfied with their education.

While many feel that loans are a burden and wish they had borrowed less, a majority are satisfied with their education.

While a minority feel that loans are a burden and wish they had borrowed more, a minority are satisfied with their education.

While a minority feel that loans are a burden and wish they had borrowed more, a majority are satisfied with their education.

Explanation / Answer

a.
given that,
sample size(n)=1298
success rate ( p )= x/n = 0.58
CI = confidence interval
confidence interval = [ 0.58 ± 1.96 * Sqrt ( (0.58*0.42) /1298) ) ]
= [0.58 - 1.96 * Sqrt ( (0.58*0.42) /1298) , 0.58 + 1.96 * Sqrt ( (0.58*0.42) /1298) ]
= [0.553 , 0.607]

we have more than half of result that agrees it feels feel burdened & we are 95% sure that the interval
[ 0.553 , 0.607] contains decision

b.
given that,
sample size(n)=1298
success rate ( p )= x/n = 0.543
CI = confidence interval
confidence interval = [ 0.543 ± 1.96 * Sqrt ( (0.543*0.457) /1298) ) ]
= [0.543 - 1.96 * Sqrt ( (0.543*0.457) /1298) , 0.543 + 1.96 * Sqrt ( (0.543*0.457) /1298) ]
= [0.516 , 0.57]

we have decision that atleast 50% of studuent would you borrow loan & we are 95% sure that the interval
[0.516 , 0.57] contains decision

c.
given that,
sample size(n)=1298
success rate ( p )= x/n = 0.336
CI = confidence interval
confidence interval = [ 0.336 ± 1.96 * Sqrt ( (0.336*0.664) /1298) ) ]
= [0.336 - 1.96 * Sqrt ( (0.336*0.664) /1298) , 0.336 + 1.96 * Sqrt ( (0.336*0.664) /1298) ]
= [0.31 , 0.362]
d.
given that,
sample size(n)=1298
success rate ( p )= x/n = 0.599
CI = confidence interval
confidence interval = [ 0.599 ± 1.96 * Sqrt ( (0.599*0.401) /1298) ) ]
= [0.599 - 1.96 * Sqrt ( (0.599*0.401) /1298) , 0.599 + 1.96 * Sqrt ( (0.599*0.401) /1298) ]
= [0.572 , 0.626]
e.
given that,
sample size(n)=1298
success rate ( p )= x/n = 0.592
CI = confidence interval
confidence interval = [ 0.592 ± 1.96 * Sqrt ( (0.592*0.408) /1298) ) ]
= [0.592 - 1.96 * Sqrt ( (0.592*0.408) /1298) , 0.592 + 1.96 * Sqrt ( (0.592*0.408) /1298) ]
= [0.565 , 0.619]
------------------

Related Questions

Navigate

• Browse (All)
• Browse T
• Subjects

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.