Edit View History Bookmarks Window Help 96%-. Sun 2: mathxl.com MAT-240-R1033-17

Question

Edit View History Bookmarks Window Help 96%-. Sun 2: mathxl.com MAT-240-R1033-17Ew1 William Ballew 1a8/1 7 2:22 PM Homework: 5-2 MyStatLab: Module Five Problem Set Save Score: 0 of 5 pts IO of 14 (14 complete) Hw score: 68.21%, 44.33 of 65 pts 11.3.3 Assuming that both populations are normally distributed·construct a 90% confidence interval about ,-P2. ( represents the mean of the experimental group and 2 represents the mean of the control group.) Question Help * 29 48.1 6.5 Control 19 49.2 12.4 The confidence interval has a lower bound ofand an upper bound of (Use ascending order. Round to two decimal places as needed) Enter your answer in the edit fields and then click Check Answer Check Answer Clear All All parts showing

Explanation / Answer

SE = sqrt [ s21 / n1 + s22 / n2 ] = 3.090231

Degree of freedom, df = (s12/n1 + s22/n2)2 / { [ (s12 / n1)2 / (n1 - 1) ] + [ (s22 / n2)2 / (n2 - 1) ] } = 24.5528 = 25

tcrit = +/- 1.7081

90% CI = -1.1 +/- 1.7081*3.090231 = (-6.38, 4.18)

Related Questions

Navigate

• Browse (All)
• Browse E
• Subjects

---

---

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.