We are interested in the number of orange M&M’s selected from a sample of ten. U
ID: 3329631 • Letter: W
Question
We are interested in the number of orange M&M’s selected from a sample of ten. Use the “Per M&M’s Official” column to find the probability of selecting an orange.
Let X = the number of orange M&M's selected
X ~ Binomial (n=10, p=0.20 )
Question 1
What is n? Give the numerical value.
Question 2
What is p? Give in the form of a decimal.
Question 3
What is the average number of orange M&M’s?
Question 4
What is the standard deviation of orange M&M’s? Give solution to three decimal places.
Question 5
Find the probability of selecting seven or more orange M&M’s out of a sample of ten. Give solution to four decimal places.
Question 6
When sampling 10 M&M’s, what is the probability of getting exactly three that are orange? Give solution to four decimal places.
Question 7
What is the probability that the number of orange M&M’s drawn out of ten is more than two, but less than eight? Give solution to four decimal places.
Question 8
Find the probability of selecting more than 3 orange M&M’s out of a sample of ten. Give solution to four decimal places.
Question 9
BONUS: When sampling 10 M&M’s, what is the probability of getting eight that are not orange? Give solution to four decimal places.
Doc Word Home X Cu Find pboard Style Ed unpExplanation / Answer
This is a Binomial Distribution
a) n = 10, since number of trials are 10 or the sample size is 10
b) p = 0.2, given probability per M&M official
c) average number of orange M&M is given by = np (Mean for binomial distribution is given by np)
average number of orange M&M is given by = 10*.2 = 2
d) standard deviation of orange M&M = (np(1-p))1/2
(Standard Deviation for binomial distribution is given by np(1-p))
standard deviation of orange M&M = (10*.2*.8)1/2
standard deviation of orange M&M = (1.6)1/2
standard deviation of orange M&M = 1.265
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