1 -t points WowskylntroSat1 6.HW.060 My Notes Ask Your The patient recovery time
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1 -t points WowskylntroSat1 6.HW.060 My Notes Ask Your The patient recovery time from a particular surgical procedure is normally distributed with a mean of 5.1 days and a standard deviation of 1.9 days. What is the median recovery time? days Additional Materials Secton 6.1 My Notes Ask Your The patient recovery time from a particular surgical procedure is normally distributed with a mean of 4.8 days and a standard deviation of 3.6 days. What is the z-score for a patient who takes 7 days to recover? (Round your answer to two decimal places.) Additional Materials Section 6.1 -/1 points BowskylntroStat1 6.HW 062 The length of time it takes to find a parking space at 9 A.M. follows an unknown distribution with a mean of five minutes and a standard deviation of two minutes. When the mean is significantly greater than the standard deviation, which of the following statements is true? (Select all that apply.) My Notes Ask Your O The data cannot follow the uniform distribution OThe data cannot follow the normal distribution O The data cannot follow the exponential distribution. Additional Materials Section 6.1Explanation / Answer
1. Median corresponds to 50th percentile, which means P(X<=x)=0.50. Find z score whose area is closest to 0.50. The z score corresponding to 0.50 is 0. Substitute 0 in the following z score formula and obtain the raw score, which gives the value of the median.
z=(X-mu)/sigma, where, X is the raw score, mu is population mean, sigma is population standard deviation.
0=(X-5.1)/1.9, X=5.1 days.
2. Substitute mu=4.8 and sigma=3.6 and X=7 in the Z score formula to ocmpute the required Z score.
Z=(7-4.8)/3.6=0.61
3. Check first and third option. To be precise, exponential distribution and uniform distribution has nothing to do with standard deviation.
4. Check No. Per emperical rule, for normal distribution, 68% of data fall within 1 standard devaition, 95% of data fall within 2 standard deviation and 99.7% of data fall within 3 standard deviation. Therefore, given mean=7 and standard deviation=3, 99.7% data fall within -2 and 16 minutes. Therefore, there is no surprise, if one find parking in less than 1 minute.
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