Can somone help with this assignment: Research Question: Does the number of prev

Question

Can somone help with this assignment:

Research Question:

Does the number of previous premature labors (continuous - ratio) (response) relate to having presence of uterine irritability (categorical- dichotomous) (explanatory)?

1. State The parameter of interest:

2. State the hypotheses:

3. Test statistic & P-value:

(do a t-test)

4. Decide whether to reject or not reject the null hypothesis

5. Clearly state a conclusion in the context of the problem

Here is the Data: (number of previous prmature labors: 0-3) (Presence of uterine irritability: 0=NO, 1=YES)

0

Number previous premature labors 0 0 0 0 0 0 0 0 0 0 0 0 0 1 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 1 1 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 2 1 0 0 2 1 2 0 0 0 0 0 0 1 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 3 0 0 0 0 0 0 0 0 1 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 1 0 0 0 1 0 0 1 0 0 0 1 0 0 0 2 0 0 0 0 0 1 0 0 2 0 0 1 0 1 0 1 0 0 0 1 0 0 1 1 1 0 1 0 0 0 0 0 0 1 0 0 1 0 1 0 0 1 0 0 0 0

0

Presence uterine irritability 1 0 0 1 1 0 0 0 0 0 0 0 0 1 0 0 0 0 1 0 0 1 0 0 1 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 1 1 0 0 0 0 0 0 0 0 0 0 1 0 0 0 0 0 0 0 0 1 0 0 1 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 1 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 1 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 1 1 0 0 1 0 1 0 0 0 0 1 0 0 0 0 1 0 0 1 0 0 1 0 0 1 0 1 1 1 0 0 0 0 0 1 0 0 0 0 0 0 0 1 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0

Explanation / Answer

Chi-Square Goodness-of-Fit Test for Categorical Variable: Number previous prema

Test Contribution
Category Observed Proportion Expected to Chi-Sq
0 320 0.25 94.5 538.098
1 52 0.25 94.5 19.114
2 5 0.25 94.5 84.765
3 1 0.25 94.5 92.511

N N* DF Chi-Sq P-Value
378 1 3 734.487 0.000

Define the parameter of interest:The proportion associated with each category you want to test.

2. State the hypotheses

·    H0 : Data follow a multinomial distribution with certain proportions

·    H1 : Data do not follow a multinomial distribution with certain proportions

3. Determine the test statistic and p-value considering any necessary assumptions

From above output: P-value-0.0000

4. Decide whether to reject or not reject the null hypothesis

P-value < 0.05 we reject the null hypothesis. you can conclude that there is enough evidence exists to reject the null hypothesis.

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