Ted is not particularly creative. He uses the pickup line \"If I could rearrange

Question

Ted is not particularly creative. He uses the pickup line "If I could rearrange the alphabet, I'd put U and I together." The random variable x is the number of girls Ted approaches before encountering one who reacts positively. Determine whether the table describes a probability distribution. If it does, find its mean and standard deviation

Part a: Find the mean of the random variable x. Select the correct choice below and, if necessary, fill in the answer box to complete your choice. (round to one decimal place as needed)

Part b: Find the standard deviation of the random variable x. Select the correct choice below and, if necessary, fill in the answer box to complete your choice.

Ted is not particularly creative. He uses the pickup line "If I could rearrange the alphabet, I'd put U and I together." The random variable x is the number of girls Ted approaches before encountering one who reacts positively. Determine whether the table describes a probability distribution. If it does, find its mean and standard deviation

x 1 2 3 4 5 p(x) 0.001 0.011 0.137 0.251 0.357

Part a: Find the mean of the random variable x. Select the correct choice below and, if necessary, fill in the answer box to complete your choice. (round to one decimal place as needed)

Part b: Find the standard deviation of the random variable x. Select the correct choice below and, if necessary, fill in the answer box to complete your choice.

Explanation / Answer

Sum of probabilities x = 0.001 + 0.011 + 0.137 + 0.251 + 0.357 = 0.757

Since the probabilities don't sum up to 0.757, this is not a probability distribution.

Mean = xp(x) = 1 * 0.001 + 2 * 0.011 + 3 * 0.137 + 4 * 0.251 + 5 * 0.357

= 3.223

= 3.2

Variance 2 = x2p(x) - 2 = 1 * 0.001 + 4 * 0.011 + 9 * 0.137 + 16 * 0.251 + 25 * 0.357 - 3.223 * 3.223

= 3.831271

Standard deviation = 3.831271 = 1.957.

(Please choose the nearest value.)

x 1 2 3 4 5 p(x) 0.001 0.011 0.137 0.251 0.357

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