(initial data rate (Rate 5) Using the following rate and law - AHCroHD , letermi

Question

(initial data rate (Rate 5) Using the following rate and law - AHCroHD , letermine the value rate k unit). of the constant(with correct 2MnO: + SHCO+ 6H 4 2Mn++ 10CO, +8Hzo Expt. [MnO, J. (HLCO). [H]. Initial Rate MIs) 1 x 1031 10 1.0 2 x 10 2x 10 1 x 10' 2 x 10 2x 103 8 x 10 2x 10 2 x 10 2.0 1.6 x 103 2 x 10 1.0 1.0 A) 2x 105 M2g1 B) 2x 10 " Mos ' c) 2x 105 Ms D) 200 MEs " E) 200 Ms (6) A first-order reaction a rate constantk.023 '. What is the length half has , , of Ominof -life for this reaction? A) 41 min B) 30. min c) 2.2 h D) 51 min E) 20. min In IA - it arAN (7) A first-order reaction is 60.0% complete at the end of 40.8 minutes. What is the value of the rate constant (in mind)? A) 2.25 x 102 B) 1.25 x 10 C) 79.9 D) 44.5 E) 22.5 SYS at 40.

Explanation / Answer

Q.5

Rate = k [H2C2O4]2 {H+]

For experiment 1

Rate = 2 x 10-4

[H2C2O4] = 10-3

[H+] = 1.0

so,

2 x 10-4 = k * [1 x 10-3]2 * 1

k = 200 M-2 sec-1

Question 6

For first order reaction

t1/2 = 0.693/ k

t1/2 = 0.693/ 0.023 = 30.13 min

Option B is correct.

Question 7

For first order reaction

[A]=[A]0­e­kt

[A]/[A]0­ = e-kt

[A] = 0.6 [A]0­ [ as per question]

0.6 = e-kt where t = 40.8 minutes

ln (0.6) = - k * 40.8

k = 1.25 x 10-2 min-1

Option B is correct.

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