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The time spent (in days) waiting for a kidney transplant for people ages 35-49 c

ID: 3334512 • Letter: T

Question

The time spent (in days) waiting for a kidney transplant for people ages 35-49 can be approximiated by the normal distribution, as shown in the figure to the right. (a) What waiing time represents the 85th percentile? (b) What waiing time represents the first quartile? -1688 200.3 1588 1688 1788 Days a) The waiting time that represents the 85th percentile is days Round to the nearest integer as needed) b)The waitng time that represents the first quartie isdays Round to the nearest integer as needed.)

Explanation / Answer

Given mean =1688; standard deviation = 209.3

a) 98th percentile is P(z<z*) =0.85

=P(z<(x-1688)/209.3)=0.85

85 the percentile is = 1.036*209.3 + 1688( since z=( x- mean)/sd)

=1904.83 nearly equal 1905

b) first quarile is P(z<z*) =0.25

from standard normal tables P(Z<-0.67499) =0.25

first quartile value is = -0.67499*209.3 + 1688 = 1546.72 rounding off nearly equal to 1547

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