Homework: HW #10 Ch. 7.3 & 8.1 (Week of Oct. 16th) Save Score: 0 of 1 pt 5 of 10
ID: 3334788 • Letter: H
Question
Homework: HW #10 Ch. 7.3 & 8.1 (Week of Oct. 16th) Save Score: 0 of 1 pt 5 of 10 (2 complete) Hw Score: 0%, 0 . 7.3.57-T Question Help According to the most recent data, 9.4% of engineers (electrical, mechanical, civil, and industrial) were women. Suppose a random sample of 75 engineers is selected. a. How likely is it that a random sample of 75 people will contain 9 or more women in these positions? b. How likely is it that the random sample will contain fewer than 5 women in these c. If the random sample included 150 engineers, how would this change your answer to part b? a. The probability of getting a sample of 75 with 9 or more women is (Round to four decimal places as needed.)Explanation / Answer
p = 0.094 n = 75
= np = 0.094 * 75 = 7.05
= (np(1-p)) = (7.05*0.906) = 2.5273
a. X = 9
Z = (X - ) /
= (9 - 7.05) / 2.5273
= 1.95 / 2.5273
= 0.7716.
Probability (right tailed) = 0.2202.
b. X = 5
Z = (X - ) /
= (5 - 7.05) / 2.5273
= -2.05 / 2.5273
= -0.8111.
Probability = 0.2087.
c. p = 0.094 n = 150
= np = 0.094 * 150 = 14.1
= (np(1-p)) = (14.1*0.906) = 3.5742
X = 5
Z = (X - ) /
= (5 - 14.1) / 3.5742
= -2.5460
Probability = 0.0054.
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