1. Iron-deficiency anemia is the most common form of malnutrition in developing

Question

1. Iron-deficiency anemia is the most common form of malnutrition in developing countries, affecting about 50% of children and women and 25% of men. Iron pots for cooking foods had traditionally been used in many of these countries, but they have been largely replaced by aluminum pots, which are cheaper and lighter. Some research has suggested that food cooked in iron pots will contain more iron than food cooked in other types of pots. One study designed to investigate this issue compared the iron content of some Ethiopian foods cooked in aluminum, clay, and iron pots. One of the foods was yesiga wet, beef cut into small pieces and prepared with several Ethiopian spices. The iron content of four samples of yesiga wet cooked in each of the three types of pots is given below. The units are milligrams of iron per 100 grams of cooked food. data373.dat

(a) Make a table giving the sample size, mean, and standard deviation for each type of pot. Is it reasonable to pool the variances? Note that with the small sample sizes in this experiment, we expect a large amount of variability in the sample standard deviations.

(b) Run the analysis of variance. Report the F statistic with its degrees of freedom and P-value. What do you conclude? (Round your test statistic to two decimal places. Round your P-value to three decimal places.)
F =
P =

Conclusion: There is

statistically significant difference between the three treatment means at the = .05 level.

DAT373.dat

2. Many studies have suggested that there is a link between exercise and healthy bones. Exercise stresses the bones and this causes them to get stronger. One study examined the effect of jumping on the bone density of growing rats. There were three treatments: a control with no jumping, a low-jump condition (the jump height was 30 centimeters), and a high-jump condition (60 centimeters). After 8 weeks of 10 jumps per day, 5 days per week, the bone density of the rats (expressed in mg/cm3 ) was measured. Here are the data. data444.dat

(b) Run the analysis of variance. Report the F statistic with its degrees of freedom and P-value. What do you conclude? (Round your test statistic to two decimal places and your P-value to three decimal places.)

Conclusion: There is a statistically significant difference between the three treatment means at the = .05 level.

For both equations I cannot find the F and P values listed in Part b of both.

Type of pot n s Aluminum 4 1.9675 0.52665 0.263325 Clay 4 2.495 0.66214 0.33107 Iron 4 4.7625 0.11087 0.055435

Explanation / Answer

b)

hence F =36.35

p value =0.0000

2)

hence F =41.16

abnd p value =0.0000

i ni Xi Si^2 ni*(Xi- grand mean)^2 (ni-1)*Si^2 Aluminum 4 1.9675 0.277 4.906 0.832 Clay 4 2.495 0.438 1.346 1.315 Iron 4 4.7625 0.012 11.391 0.037 Weighted mean 3.075 17.642 2.184 SSG SSE Source of variation SS df MS F P value F crit treatment 17.642 2 8.821 36.347 0.0000 4.2565 error 2.184 9 0.243 total 19.827 11

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