> HW/6 STAT 201 : CI\'s Sam \"A HW6 STAT 201 : Cl\'s & S e Numvber 4 Please! Che

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> HW/6 STAT 201 : CI's Sam "A HW6 STAT 201 : Cl's & S e Numvber 4 Please! Che / a x X c ww.webassign net/web/Student/Assignment Responses last?dep-17382736?course-443014635852&target-web;/Student/Assignment Responses/last?dep#173827368 a The BATF wishes to estimate the true average lead level for California wines to within 24 parts per billion at a 95% level of confidence? Based on the BATF's criteria, the number of wine specimens that should be tested is: Note: you should carry at least 5 decimal precision for any intermediate calculations then round your answer as indicated in the problem 5. -3 points My Notes A random sample of n = 12 men between 30 and 39 years old is asked to do as many situps as they can in one minute. Table 1 reports the descriptive statistics for this study: Table 1: Descriptive statistics for the situps stud situ 12 48.6 12.4 3.58 The investigators would like to construct a 95% confidence interval for the true average number of sit ups men in this age group can complete in 1 minute. Note: you should carry at least 5 decimal precision for any intermediate calculations. Then round your answers as indicated. A) The margin of error is: Round your answer to the nearest hundredth B) The corresponding 95% confidence interval for the true population mean is When setting confidence intervals for discrete data investigators will round the lower endpoint down to the next lowest integer and the upper endpoint up to the next highest integer. You should express your answers using this convention to sit-ups 6. -12 points My Notes Acrylic bone cement is sometimes used in hip and knee replacements to fix an artificial joint in place. The force required to break an acrylic bone cement bond was measured for n = 20 specimens under specified conditions, and the resulting mean and standard deviation were 302.09 Newtons and 40.37 Newtons, respectively. Assuming that the breaking force under these Type here to search 10/24/20172

Explanation / Answer

The statistical software output for this problem is:

One sample T summary confidence interval:
: Mean of population

95% confidence interval results:

Hence,

a) Margin of error = (56.478584 - 40.721416)/2 = 7.88

b) 95% confidence interval for true population mean is: 40 to 57 sit - ups

Mean Sample Mean Std. Err. DF L. Limit U. Limit 48.6 3.5795717 11 40.721416 56.478584

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