Now we can test each mean against each other mean, and use a Bonferroni correcti

ID: 3336130 • Letter: N

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Now we can test each mean against each other mean, and use a Bonferroni correction to control the family-wise error rate at =0.05. Recall from above that: 18+ = 7.6 16+ = 6.5 "r12+ = 5.6 -7 +-5.3 For each comparison, calculate the difference in sample means, the t-test statistic (rounded to three decimal places), and the p-value. The standard error and degrees of freedom for each comparison are provided difference in sample standard error of degrees of t-test statisticfreedom two sided p-value Parameter means difference 2.245 0.49 40 16+ Enter a number 4.082 0.49 39 12+ 4.694 2.3 0.49 39 16,- 12+ 9 0.50 37 2.4 0.50 588 0.51 36

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from above: below are two sided p values corresponding to column:

difference in sample means std error t-test degree of freedom p value 1.1 0.49 2.245 40 0.03037 2 0.49 4.082 39 0.00021 2.3 0.49 4.694 39 0.00003 0.9 0.5 1.800 37 0.08002 1.2 0.5 2.400 37 0.02154 0.3 0.51 0.588 36 0.56005

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Now we can test each mean against each other mean, and use a Bonferroni correcti

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