for normal distribution with a mean of 128 and a standard deviation of 36, what

Question

for normal distribution with a mean of 128 and a standard deviation of 36, what is the z value (distance from the mean) for a random value to be 174? (use 2 decimal digits) for normal distribution with a mean of 128 and a standard deviation of 36, what is the z value (distance from the mean) for a random value to be 174? (use 2 decimal digits) for normal distribution with a mean of 128 and a standard deviation of 36, what is the z value (distance from the mean) for a random value to be 174? (use 2 decimal digits)

Explanation / Answer

Solution:- mean of 128 and a standard deviation of 36,X = 174

Formula z = (x – ) /

= (174 - 128)/36

= 46/36

z = 1.28

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