d) 36.26% 16 Gpt) The table below gives the frequencies of occurrences for each

Question

d) 36.26% 16 Gpt) The table below gives the frequencies of occurrences for each letter in an amount of written material consisting of 10,000 letters. We are interested in investigating which letters occur most frequently A 820 J 10 S 600 B 140 K 40 T 1050 C 280 L 340 U250 D 380 M 250 V 90 E 1300 N 700 W 150 F 300 O 800 X 20 G 200 P 200 Y 200 H 530 Q10 Z 7 I 630 R 680 Which graphical technique would be most useful for comparing the frequency of use of each letter a)tem and leaf plot percentage polygon e) boxplot d) pie chart 7) (5pt) If the Z score of a number x is equal to 2.then a) x is 2 above the mean b) x is 2 below the mean x is 2 standard deviations above the mean d) x is 2 standard deviations below the meatn

Explanation / Answer

Bar and pie charts are used for qualitative (category) data.

height of bar or size of pie represnts frequency

Here frequencies given

USE PIE CHART.

stem and leaf plot,scatter plot are used for quantitative variables.

Stem-and-leaf plots are a method for showing the frequency with which certain classes of values occur. You could make a frequency distribution table or a histogram for the values, or you can use a stem-and-leaf plot and let the numbers themselves to show pretty much the same information.

To create a frequency polygon, start just as for histograms, by choosing a class interval. Then draw an X-axis representing the values of the scores in your data

Box plot for detecting outliers and getting the five num summary which includes minimum value,Q1,,median,Q3 and maximum value

In this problem

use PIE CHART

ANS :

pie chart

Solution2:

Z=X-mean/sd

here z scores are standardised scores we got the value of z as

z

Z=2

a positive value

means its 2 standard eviations above mean

if it would have beena negative value it is

z=-2

2 standard deviations below mean

ANS 2 STANDARD DEVITAIONS ABOVE MEAN

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