A company makes windows for use in homes and commercial buildings. The standards

Question

A company makes windows for use in homes and commercial buildings. The standards for glass thickness call for the glass to average 0.325 inch with a slandard deviation equal to 0.055 inch. Suppose a random sample of n 52 windows yields a sample mean of 0.345 inch. Complele parts a and b below. a. What is the probability of x 20.345 if the windows meet the standards? PG 20.345)- (Round to four decimal places as needed b. Based on your answer to part a, what would you conclude about the population of windows? ls it meeting the standards? (A result is unusual if it has a probability lass than 0.05. The population af windows | | meeting the standards, because sample af 52 windows with, samle mean ara 345 inch | if the population actually had a mean of 0.325 inch and a standard deviation of 0.055 inch. standard

Explanation / Answer

Answer to the question :

Sample mean = .345
n = 52
Population mean = .325
pop. stdev = .055

a. P(X>=.345) = P(Z>= (.345-.325)/(.055/sqrt(52)) = P(Z>=2.622) = 1-.9956 = .0044

b. The population of windpws is not meeting the standards, because a sample of 52
windows with a sample mean of 0.345 inch has less than .05 significance if the
population actually had a mean of .325 inch and a standard deviation of .055 inch

Related Questions

Navigate

• Browse (All)
• Browse A
• Subjects

---

---

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.