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A sample of 30 students are tested to determine the percentage of students who a

ID: 3337711 • Letter: A

Question

A sample of 30 students are tested to determine the percentage of students who are uninformed about international news.the 99% confidence interval for this data is 58+8.8068,[49.1932,66.8068] . Sample Mean=58 Standard deviation =17.5 Interpret the confidence interval . A sample of 30 students are tested to determine the percentage of students who are uninformed about international news.the 99% confidence interval for this data is 58+8.8068,[49.1932,66.8068] . Sample Mean=58 Standard deviation =17.5 Interpret the confidence interval . Sample Mean=58 Standard deviation =17.5 Interpret the confidence interval .

Explanation / Answer

Sample Mean=58

Standard deviation =17.5

Sample size = 30

Confidence interval is [49.1932,66.8068].

The confidence interval tells us that we can estimate with 99% confidence that the mean percentage of students who are uninformed about international news is between 49.1932 and 66.8068.

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