a blue opaque jar contains the following jellybeans: 15 red 12 green 8 black 10

Question

a blue opaque jar contains the following jellybeans: 15 red 12 green 8 black 10 yellow 13 orange 7 purple
A) probability of randomly selecting a red jellybean from jar B) probability of randomly selecting a black or a purple jelly bean from jar C) probability of randomly selecting a green and an orange (WITH REPLACEMENT) D) probability of randomly selecting a green and an orange (WITHOUT replacement) E) the probability of randomly selecting two red without replacement a blue opaque jar contains the following jellybeans: 15 red 12 green 8 black 10 yellow 13 orange 7 purple
A) probability of randomly selecting a red jellybean from jar B) probability of randomly selecting a black or a purple jelly bean from jar C) probability of randomly selecting a green and an orange (WITH REPLACEMENT) D) probability of randomly selecting a green and an orange (WITHOUT replacement) E) the probability of randomly selecting two red without replacement a blue opaque jar contains the following jellybeans: 15 red 12 green 8 black 10 yellow 13 orange 7 purple
A) probability of randomly selecting a red jellybean from jar B) probability of randomly selecting a black or a purple jelly bean from jar C) probability of randomly selecting a green and an orange (WITH REPLACEMENT) D) probability of randomly selecting a green and an orange (WITHOUT replacement) E) the probability of randomly selecting two red without replacement

Explanation / Answer

Answer to the question is as follows:

a. P( selecting red bean) = 15/(15+12+8+10+13+7) = .2308

b, P( black or purople ) = (8+7)/(15+12+8+10+13+7) = .2308

c. P( green and an orange with replacement) = (12/65) * (11/65) = .0312

d. P( green and an orange with replacement) = (12/65) * (11/64) = .0317

e. P( 2 reds without replacement) = (15/65)*(14/64) = .0505

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