Sam and Penny are 4th graders surveying their spoils at lunch on the day after H

Question

Sam and Penny are 4th graders surveying their spoils at lunch on the day after Halloween. They realize that Sam has a bag of 10 M&M's, and Penny has a bag of 10 Skittles. They want to share some of their candy with each other, so Sam takes some out of his bag, and puts them into Penny's bag. After shaking her bag up, Penny randomly takes the same number of candies from her M&M-and-Skittle mixture and puts them back into Sam's bag, so that each of them once again has 10 pieces of candy. They want to know who has more of the other person's candy type.

Suppose Sam gives Penny 1 piece of candy, and Penny gives Sam 1 piece of candy back. What are the possible outcomes?

Suppose Sam gives Penny 2 candies, and Penny gives Sam 2 candies back. What are the possible outcomes?

Suppose Sam gives Penny 3 candies, and Penny gives Sam 3 candies back. What are the possible outcomes?

Explanation / Answer

Solution- (a) When sam gives 1 M &M' and penny may give M&M' or skittle so final outcome can be either

10 M&M' with sam and 10 skittles with penny

or 9 M&M' and 1 skittle with sam and 9 skittles and 1 M&M' with penny

(b) When sam gives 2 M &M' and penny may give both skittles back

or both M&M's back

or 1 skittle and 1 M&M' back, then final outcomes are-

10 M&M' with sam and 10 skittles with penny

or 8 M&M' and 2 skittle with sam and 8 skittles and 2 M&M' with penny

or 9 M&M' and 1 skittle with sam and 9 skittles and 1 M&M' with penny

(c) When sam gives 3 M &M' and penny may give all skittles back

or all M&M's back

or 1 skittle and 2 M&M' back,

or 2 skittle and 1 M&M' back,

then final outcomes are-

10 M&M' with sam and 10 skittles with penny

or 8 M&M' and 2 skittle with sam and 8 skittles and 2 M&M' with penny

or 9 M&M' and 1 skittle with sam and 9 skittles and 1 M&M' with penny

or or 7 M&M' and 3 skittle with sam and 7 skittles and 3 M&M' with penny

Answers

TY!

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