MTH 265- FA17 (CRN 4949 Test: Chapter 4 Test Time Remaining: 00:37:32 Sbm Te Thi

Question

MTH 265- FA17 (CRN 4949 Test: Chapter 4 Test Time Remaining: 00:37:32 Sbm Te This Question: 1 pt 19 of 20 (11 completel This Test: 20 pts possibi he indicated probablies using the geometric distribution, the Poisson distribution, or the binomiai distibution. Then determine if the averts are nu.a probabilties If convenient, use the appropriate probaslbity lable or lechnckogy lo fnd the The mean number of births per minude in a country in a recent year was about three Find the probablity that the namber of brths in any given mnute is (a) exacty four, Oh) at least faur, and ie) mo han our Round to four decimel pleces as needed.) Round to four decimal places asneeded Round to four decimal places as neoded) Which of the events are unusual? Select all that apply A. The event n parte-javusuel. B. The evert r, part (b)suntual C. The avent in part (c) is unusua D.. None of the everts are unusual Click to select your anewerjs).

Explanation / Answer

= 3

This is poisson distribution.

P(X = x) = e- * x / x!

a) P(X = 4) = e-3 * 34 / 4! = 0.1680

b) P(X > 4) = 1 - [P(X = 0) + P(X = 1) + P(X = 2) + P(X = 3)]

                   = 1 - [e-3 * 30 / 0! + e-3 * 31 / 1! + e-3 * 32 / 2! + e-3 * 33 / 3!]

                   = 1 - 0.6472

                   = 0.3528

c) P(X > 4) = 1 - [P(X = 0) + P(X = 1) + P(X = 2) + P(X = 3) + P(X = 4)]

                   = 1 - [e-3 * 30 / 0! + e-3 * 31 / 1! + e-3 * 32 / 2! + e-3 * 33 / 3! + e-3 * 34 / 4!]

                   = 1 - 0.8153

                   = 0.1847

d) Option-D) Because none of the probability is less than 0.05 or greater than 0.95

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