D Question 28 1 pts The manager of the dairy section of a large supermarket chos

Question

D Question 28 1 pts The manager of the dairy section of a large supermarket chose a random sample of 300 egg cartons and found that 48 cartons had at least one broken egg. Let p denote the proportion of all cartons which have at least one broken egg. Find a point estimate for p and also construct a 90% confidence interval for p. 0.840, (0.799,0.881) 0.160, (0.119, 0.201) 0.160, (0.125, 0.195) 48, (0.125, 0.195) 48,(0.119,0.201) D Question 29 1 pts The manager of the dairy section of a large supermarket chose a random sample of 300 egg cartons and found that 48 cartons had at least one broken egg. Let p denote the proportion of all cartons which have at least one broken egg. which of the following actions would result in a confidence interval wider than the 90% confidence interval computed above? O computing an 85% confidence interval rather than a 90% confidence interval Computing an 95% confidence interval rather than a 90% confidence interval None of the above Increasing the sample size Computing an 80% confidence interval rather than a 90% confidence interval

Explanation / Answer

Q.1 Point estimate p^ = 48/300 = 0.16

90% confidence interval = p^ +- Z90% sqrt[p^ * (1-p^)/N]

= 0.16 +- 1.645 * sqrt[0.16 * 0.84/300]

= 0.16 +- 1.645 * 0.0212

= (0.125, 0.195)

Option C is corect.

Question 2

For a wider confidence interval, we have to increase the value of confidence interval or decrease the sample size.

Option B is correct.

Related Questions

Navigate

• Browse (All)
• Browse D
• Subjects

---

---

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.