S. Suppose, according to a 2016 demographic report, the average U. S. housebold
ID: 3338436 • Letter: S
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S. Suppose, according to a 2016 demographic report, the average U. S. housebold spends s90 per day. Suppose you recently took a random sample of 30 housebolds in Huntsvile and the results revealed a menn of $86.50. Suppoee the standard deviation is known to be 514.50. Using a 0.05 level of sigaificance, can it be concluded that the average amount spent per day by U.S. households has decreased? 6. Suppose a production live operates with a mean filling weight of 16 ounces per container Since over- or under-filling can be dangerous, a quality control inspector samples 30 items to determine whether or not the filling weight has to be adjusted. The sample revealed a mean of 16.32 ounces and the standard deviation 0.8 ounces. Using a 0.10 level of sigaificance, cnn it be concluded that the process is out of control (not equal to 16 ounces)? 7·The salesman claims that the average weight of each can of the drink is at least 20 ounce. and the standard deviation is 3 ounce. To test the claim, you have checked 20 cans, and found the average is only 18.6 ounce. Can you reject the claim at significance level 0.057 8. A professor waats to know if her introductory statistics class has a good grasp of basic math. 10 students are chosen at random from the class and given a math proficiency test. The professor wants the class to be able to score above 70 on the test. From these 10 students, she find average is: 73.17, standard deviation is: 13.16. Can the professor have 90 tercent confidence that the mean score for the class on the test would be above 70?Explanation / Answer
5) Ho: >= 90
Ha: < 90
Test statistic, z = (x - )/(/sqrt(n)) = (86.5 - 90)/(14.5/sqrt(30)) = -1.32
p-value (one sided) = 0.0934
0.0934 > 0.05, Fail to reject null hypothesis, there is no sufficient evidence to suggest average amount spent per day has decreased
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