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The Puliman Mig. Inc three-station work cell lustrated n the figure below/ as tw

ID: 333941 • Letter: T

Question

The Puliman Mig. Inc three-station work cell lustrated n the figure below/ as two machines at station 1 in paratildl go through only one of the two machines before proceeding to station 2) 20 min/unit Station 1 Machine A Station 2Station 3 8 min/unit Machine B12 min/urit 20 min/unit The manager, Ms. Hartley, has asked you to evaluate the system if she adds a parallel machine at station 2 a) The process cycle time of the new work cell is (40 minutes (enter your response as a whole number) b) The system process time of the new work cell is 12 minutes per unit (enter your response as a whole number) c) If the firm operates 8 hours per day, 6 days per week, the weekly capacity of the work cell with the second machine at workstation 2 is 48 units (enter your response as a whole number) d) If the firm operates 8 hours per day, 6 days per week, the weekly capacity of the work cell without the second machine at workstation 2 is 240 units (enter your response as a whole number) Enter your answer in each of the answer boxes

Explanation / Answer

A. Process Cycle time between two units. It is determined by the cycle time of bottleneck process.

Cycle time of station 1 = 20min/ unit /2 = 10min/unit

Cycle time of station 2 = 12min/ unit /2 = 6min/unit

Cycle time of station 3 = 8min/ unit

Hence process cycle time = 10min

B. System process time - The time a product spends on the workstation.

= System process cycle time = Time spent on station 1 + Time spent on station 2 + Time spent on station 3

= 20+12+8

=40 min

C. Total Available time in a week = 8*60*6 min = 3840 min

Cycle time with second machine at station 2 = 10min/ unit

Capacity = (Total Available time in a week)/ (Cycle time with second machine at station 2)

= 3840/10

= 384 Unit

D. Total Available time in a week = 8*60*6 min = 3840 min

Cycle time without second machine at station 2 = 12min/ unit

Capacity = (Total Available time in a week)/ (Cycle time with second machine at station 2)

= 3840/12

= 320 Unit

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