4. One morning a customer comes into Pierre\'s and orders a random assortment of

Question

4. One morning a customer comes into Pierre's and orders a random assortment of 6 danish. At the time she comes in, there are 27 danish sitting out: 11 raspberry, 9 cheese, and 7 cinnaman. Assume the danish are not replaced after they are selected. What is the probability that the third and fifth danish selected for the customer's random assortment will be raspberry four will not be raspberry? (5 pts) , and the other Suppose that 24% of the p while 76% do not. Assume that each person is independent of the any other 5. eople that come into Pierre's order a double chocolate mochaccino, Suppose seven people show up at the coffee shop at the same time. What is the probability that exactly four of them will order the mochaccino? (4 pts) a) b) How many of the seven people do we expect to order the mochaccino? (3 pts)

Explanation / Answer

4.

P(3rd and 5th are respberry and no other respberry) = (16/27)*(15/26)*(11/25)*(14/24)*(10/23)*(13/23) = 0.02

5. This is binary disstribution with p=0.24

q=0.76

a) n=7

P(4 will order mochaccino) = (7C4)*(0.24^4)*(0.76^3) = 0.05

b) expected number of mochaccino ordered = 7*0.24 = 1.68

Related Questions

Navigate

• Browse (All)
• Browse 4
• Subjects

---

---

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.