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The experiment consists on predation. In this experiment, there are 2 treatments

ID: 3341165 • Letter: T

Question

The experiment consists on predation. In this experiment, there are 2 treatments: high and low food resource. For the “high” treatment, there were twice as many food items in the bin as for the “low” treatment. It was conducted 15 times. and then we compared how many were alive and how many died. and if it was in the low or high density of food. Based on the test done below, answer ecological reasons that explain the results. If you do not know the answer, DO NOT POST ANYTHING. THANK YOU

Please answer all four questions A),B),C),D)Ecological reasons that explain the results.

The optimal flight-initiation distance, FID is that in which the probability of starving and predation are lowest, representing a balance between foraging and fleeing.

1.Conduct an appropriate statistical test to see if there is a significant difference between the alive FIDs of high and low resource abundance? (Hint: you are testing for a significant difference between two population means)

Mean

8.833333

7.066666667

Variance

21.9697

25.68060606

Observations

12

12

Pearson Correlation

0.118583

Hypothesized Mean Difference

0

df

11

t Stat

0.944132

P(T<=t) one-tail

0.182689

t Critical one-tail

1.795885

P(T<=t) two-tail

0.365378

t Critical two-tail

2.200985

Ecological reasons that explain this results`

2. Conduct an appropriate statistical test to see if there is a significant difference between the dead FIDs of high and low resource abundance? (Hint: you are testing for a significant difference between two population means

Mean     8.25      8.5

Variance 8.25      24.3333333

Observations       4          4

Pearson Correlation          -0.83517853      

Hypothesized Mean Difference       0         

df         3         

t Stat     -0.066666667    

P(T<=t) one-tail 0.475520662     

t Critical one-tail 2.353363435     

P(T<=t) two-tail 0.951041325     

t Critical two-tail 3.182446305     

B) Ecological reasons that explain this result.

                  3. Conduct an appropriate statistical test to see if there is a significant difference between the alive no. of balls collected of high vs. low resource abundance? (Hint: you are testing for a significant difference between two population means)

Mean

4.666666667

5.16666667

Variance

4.424242424

3.42424242

Observations

12

12

Pearson Correlation

0.272491146

Hypothesized Mean Difference

0

df

11

t Stat

-0.723746864

P(T<=t) one-tail

0.242164302

t Critical one-tail

1.795884819

P(T<=t) two-tail

0.484328603

t Critical two-tail

2.20098516

Ecological reasons that explain this result.

4)Conduct an appropriate statistical test to see if there is a significant difference between the dead no. of balls collected of high vs. low resource abundance? (Hint: you are testing for a significant difference between two population means)

Mean

4

7

Variance

2

0.666667

Observations

4

4

Pearson Correlation

0.288675

Hypothesized Mean Difference

0

df

3

t Stat

-4.242641

P(T<=t) one-tail

0.011991

t Critical one-tail

2.353363

P(T<=t) two-tail

0.023981

t Critical two-tail

3.182446

D) Ecological reasons that explain this result.

Mean

8.833333

7.066666667

Variance

21.9697

25.68060606

Observations

12

12

Pearson Correlation

0.118583

Hypothesized Mean Difference

0

df

11

t Stat

0.944132

P(T<=t) one-tail

0.182689

t Critical one-tail

1.795885

P(T<=t) two-tail

0.365378

t Critical two-tail

2.200985

Explanation / Answer

Question 1:

Here as we are testing whether there is a significant difference between the alive FIDs of high and low resource abundance, therefore this is a two tailed test and therefore we will have to use the 2 sided p-value to have a conclusion of the result.

From the given output we get the critical t value as 2.200985 and the test statistic value here is computed to be: 0.944132. As the test statistic value lies within the critical value here, therefore the test statistic here states that the null hypothesis cannot be rejected here and the test is not significant.

Therefore we conclude here that we dont have sufficient evidence to support the statement that there is a significant difference between the alive FIDs of high and low resource abundance.

Question 2:

Here we are testing whether there is a significant difference between the dead FIDs of high and low resource abundance, therefore this is a two tailed test. The t statistic value here is given as -0.066666667 but the two sided critical t-value here is given as 3.182446305     

Now as    -3.182446305 < -0.066666667 < 3.182446305   

Therefore this is not a significant test as the test statistic values does not lie in the rejection region here.

Question 3:

This is similar to the above problems. Here the test statistic value is -0.723746864 but as it lies in the region (-2.20098516, 2.20098516 ) , therefore the test statistic values lies in the non rejection region here. Therefore the test is not significant here and we cannot conclude here that there is a significant difference between the alive no. of balls collected of high vs. low resource abundance.

Question 4:

Here we have the test statistic value as -4.242641 < - 3.182446, therefore the test statistic values lies here in the rejection region here. Therefore the test is significant and we can reject the null hypothesis here. We conclude here that there is a significant difference between the dead no. of balls collected of high vs. low resource abundance

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