The temperature M(t) outside a building decreases at a constant rate of 1degree

Question

The temperature M(t) outside a building decreases at a constant rate of 1degree Celcius per hour. The inside of the building is heated, and there is no other source of cooling. The heater was switched on at time t=0, when the temperature inside, T(t), was 17 degrees Celcius, and the temperature outside was 0 C. Assume that the heater generates a constant amount h= 50 000 Btu/hr of heat when it is working, the heat capacity of the building is r=1/5 degrees per thousand Btu and the time constant for heat transfer between the outside and inside of building is g=2 hr. On the basis of Newton's law of cooling,

dT(t)/dt = K(M(t) - T(t)) + rh,

Find the upper value of the temperature in the building in the time interval 0 <= t < 4 hr

Explanation / Answer

just substitute the values and u will get the answer in that formula

all the parameters are given

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