If I shot an arrow an arrow straight up into the air, it would leave my bow trav

Question

If I shot an arrow an arrow straight up into the air, it would leave my bow traveling at a rate of 110 feet per second. Assume that the arrow is so "slick", that there is no friction (or air resistance). Without gravity it would continue to travel at this speed. After 8 seconds it would have traveled 8*110 feet. But, gravity will pull it back to the earth. The gravitational pull is measured as 16t2. So the height at any time t can be measured by the function h(t) = 110t - 16t2. How high will the arrow be, before it stops moving and begins it's fall back to earth? Maximum Height =

Explanation / Answer

dh/dt = 110-16*2t = 0 => t= 110/32 d/dt(dh/dt) = -32 i.e

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