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(1) Find the approximate area under the curve of y= 2x^2 by dividing the interva

ID: 3346780 • Letter: #

Question

(1) Find the approximate area under the curve of y= 2x^2 by dividing the interval between x = 4 and x = 6 into (a) n = 5 subintervals(delta x = 0.4) and (b) n = 10 subintervals(delta x = 0.2) subintwervals, and then adding up the areas of the inscribed rectangles. The height of each rectangle may be found by evaluating the function for the proper x-value. ( Type an integer or a decimal)

Please explain steps for better understanding.

(2) Evaluate the given definite integral.

Integration 0, 1 (4x^5 - 7x^3)dx

(Type an integer or a simplified fraction) Please explain steps.

Explanation / Answer

A) area=inte(ydx) and limit from 4 to 6

area=101.33 unit ans...

B) interation((4x^5 - 7x^3)dx) limit from 0 to 1 is

{4x^6/6-7x^4/4} from 0 to 1

1.08 ans........