lll Consider the parametric curve: x = 4 - t2 y = t3 - 9t At which t value(s) is

Question

lll

Consider the parametric curve: x = 4 - t2 y = t3 - 9t At which t value(s) is the tangent to this curve vertical? (Note: If there is more than one write them as a comma separated list) t = . Write the point(s) at which the tangent is vertical.(Note: If there is more than one write them as a comma separated list, e.g. (1.2),(3,4)) . At which t value(s) is the tangent to this curve horizontal? (Note: If there is more than one write them as a comma separated list). Write the point(s) at which the tangent is horizontal.( Note: If there is more than one write them as a comma separated list, e.g. (1.2),(3,4)) .

Explanation / Answer

dx/dt = -2t

dy/dt = 3t^2 -9

so tangent is vertical at

dy/dx = 3t^2 -9 /-2t =0

t = +-3

points are (-5,0)

for tangent to be horizontal

dx/dy = 0

-2t/(3t^2 -9) = 0

t = 0

points are (4,0)

Related Questions

Navigate

• Browse (All)
• Browse L
• Subjects

---

---

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.