4:07 PM c * 61% Algorithm The following pseudocode determines whether a year is

Question

4:07 PM c * 61% Algorithm The following pseudocode determines whether a year is a leap year or a common year in the Gregorian calendar (and n the proleptic Gregorian calendar before 1582). The year variable being tested is the integer representing the number of the year in the Gregorian calendar, and the tests are arranged to dispatch the most common cases first. Care should be taken in translating mathematical integer divisibility into specific programming languages if (year is not divisible by 4) then (it is a common year) else if (year is not divisible by 100) then (i is a leap year) else if (year is not divisible by 400) then (it is a common year) else (it is a leap year) The following relational assignment statement is true if test year is a leap year and is false if test year is not a leap year Your assingment is to find a MATLAB functon for built In function. Use only one function LeapYear built In function(lest year 4)0 && (built In function(test year,100)-0 built In function(test year,400)0) Test your oode using test year 1900 and test year 2024 Make sure you only submit your code for test year 1900 Your Script ResetMATLAB Documentation 1 test year 1908 2insert a built in MATLAB function in the 3% test your code using test-year 1900 (nc 4% after pretest delete or connnent test-yea 5 you must use a specific MATLAB function s test year 2824 8 LeapYearbuilt In function test year,4) Run Script

Explanation / Answer

function x=built_in_function(test_year,n)
if rem(test_year,n)==0
x=0;
else
x=1;
end
end

>> year=1995

year =

1995

>> leap_year=built_in_function(year,4)== 0 &&built_in_function(year,100)~=0 && built_in_function(year,400==0)

leap_year =

0

>> year=2004

year =

2004

>> leap_year=built_in_function(year,4)== 0 &&built_in_function(year,100)~=0 && built_in_function(year,400==0)

leap_year =

1

>> year=2100

year =

2100

>> leap_year=built_in_function(year,4)== 0 &&built_in_function(year,100)~=0 && built_in_function(year,400==0)

leap_year =

0

>>

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