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me multiple choice questions: s] A diode at 300K with no voltage on it has this

ID: 3349612 • Letter: M

Question

me multiple choice questions: s] A diode at 300K with no voltage on it has this type of current: DRIFT DIFFUSION BOTH NEITHER 5 pts] If we decrease doping, then (choose one): [ J carrier lifetime decreases and diffusion length increases ] carrier lifetime increases and diffusion length decreases carrier lifetime decreases and diffusion length decreases [ ] carrier lifetime increases and diffusion length increases 15 pts] The depletion region: I 1 contains charges such as carriers and ionized dopants I 1 contains charges such as ionized dopants contains charges such as carriers I 1 contains no charges at all 15 pts] The units for this mystery equation are (is made up, is not a real one for this course!): ] cm/v [ ] V/cm [ ] C/cm 15 pts] If I inerease doping on both sides of a diode. [ ] all types of currents decrease I ] all types of currents increase [ ] drift increases I ] diffusion increases

Explanation / Answer

Answer:- Both

Expln:-As becuase the formed depletion region serves in creating an electric field between P and N type regions, because of which, drift current flows from one side to the other and as the diode is open circuited, net current in the diode must be zero, so inorder to counter balance the resulted drift current, an equal and opposite diffusion current will also flows in the diode.

Anaswer:- Carrier life time increases and Diffusion length also increases.

Expln:- Doping means extra carriers are injected into the pure semiconductor substance, if electrons are injected more into the diode, it increases the chances of a hole cobining with the electron, that results in low carrier life time and less diffusion lengths, simillarly decreasing the doping does the things in the opposite way, means carrier lifetime increases and diffusion length also increases

Answer:- Contains no charges at all.

Expln:-Charges in the depletion region gets neutralized by the cahrges comes from opposite region, hence we cant find any charges in the depletion region.

Answer:- V/cm

Expln:- (KT/q)ln(NaNd/Ni2) has units of Volts, Na has units of cm-3 and Ln has units of cm

Answer:- All types of currents increase.

Expln:-both Drift and Diffusion Currents are functions of Charge carrier density