3. A voltage regulator with a 6 V DC output is being used to provide power to a

Question

3. A voltage regulator with a 6 V DC output is being used to provide power to a 10 ohm resistor The dropout voltage for the voltage regulator is 1.8v ELEC ENG 1100 Analog Electronics ELEC ENG 1101 Electronic Systems IN OUT GND a. b. c. What is the minimum permissible input voltage to the voltage regulator? How much power is being absorbed by the resistor? If the voltage across the IN to OUT terminals of the regulator is the minimum value (the dropout voltage), calculate the power being absorbed by the voltage regulator. You can assume that the current into the GND terminal of the regulator is zero.

Explanation / Answer

1) the minimal permissible input voltage in volatge regulator is nothing but the output voltage + dropout voltage, so here 6V +1.8 Volts= 7.8 volts so the minimal input voltage needs to be 7.8 volts.

2) power is being absorbed by the resistor is nothing but the P= IXV where I is nothing but currrent flows through the resistor and V is nothing but the volatge drop acrros the circuit, here current is not given so P= 1.8I.

3)Power absorbed by voltage regulator = VXI where V= (Vin-Vout) so here I is not given so we can say that P=(Vin-Vout)XI = (7.8-6)*I= 1.8 voltts

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