Problem 4 (20%)-1 ) What does \"Steady State\" imply in a circle? 2) What are th

Question

Problem 4 (20%)-1 ) What does "Steady State" imply in a circle? 2) What are the KCL and KVL laws applicable for "steady-state" analysis? 3) A switching power-pole is operating in de steady-state at a duty-ratio of 0.4. The average voltage at the current-port (voltage over the diode) is 12V. What is the average voltage across the output load resistor? Justify your results with details, such as which laws are based on. 4) In a switching power-pole, the voltage at the voltage port is 300V (over the capacitor) and the average voltage at the current-port (over the diode) is equal to 160+ 40 cos(200t). Calculate the duty-ratio d(t) of this switching powe pole.

Explanation / Answer

1) steady state is the part of time response (transient + steady state) in which steady state works for (t=0) where the response becomes constant after any transitions or (transient behaviour), but in the case of circle there is only the constant work of behaviour therefore we can say that the total behaviour of circle works on steady state there is no transient behaviour, because there is no variation.

2) yes completely, we can apply KCL & KVL laws for steady state or we can say for DC circuits (because steady state meant for DC, as there is no fluctation ) but there is a condition that (KCL, KVL) laws can be apply only for resistive elements, because these laws cannot work where energy dissipates or released. these laws works where energy is conserved.

3) Duty Cycle =1-Vin/Vo   or   Vin = 12 volt & Duty cycle = 0.4 then Vo = 20 volt

since it is a DC-DC switching boost converter, which gives +10 % or -10% tolerance to the supply which boost the output voltage.

4) with the formula of as mentioned above in the answer 3

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