Question 21 Not yet answered Suppose the population mean number of days a year a

Question

Question 21 Not yet answered Suppose the population mean number of days a year an employee misses work due to illness in the U.S. is 8 with a (population) standard deviation of 2 days. A random sample of 144 employees is taken and the sample average number of days missed due to illness was 8.2 with a sample standard deviation of 4. Now suppose you do not know the value of the population mean OR population standard deviation. What is the 95% confidence interval for the population mean? Points out of 2.00 Flag question Select one: a. 8.2 ± 1.645"(2W144) b, 8.2 ± 1.645°(4W144) C. 8.2 ± 1.96"(4//144) d. 8.2t 1.96(2//144)

Explanation / Answer

By the formula

X-bar ± z ×s/(sqrt n)

=8.2±1.96×4/(sqrt 144)

So option c is correct........

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