In a survey of 2485 adults, 1875 reported that emails are easy to misinterpret,
ID: 3350513 • Letter: I
Question
In a survey of 2485 adults, 1875 reported that emails are easy to misinterpret, but only 1214 reported that telephone conversations are easy to misinterpret.Construct a 95% confidence interval estimate for the population proportion of adults who report that emails are easy to misinterpret.
Construct a 95% confidence interval estimate for the population proportion of adults who report that telephone conversations are easy to misinterpret.
In a survey of 2485 adults, 1875 reported that emails are easy to misinterpret, but only 1214 reported that telephone conversations are easy to misinterpret.
Construct a 95% confidence interval estimate for the population proportion of adults who report that emails are easy to misinterpret.
Construct a 95% confidence interval estimate for the population proportion of adults who report that telephone conversations are easy to misinterpret.
In a survey of 2485 adults, 1875 reported that emails are easy to misinterpret, but only 1214 reported that telephone conversations are easy to misinterpret.
Construct a 95% confidence interval estimate for the population proportion of adults who report that emails are easy to misinterpret.
Construct a 95% confidence interval estimate for the population proportion of adults who report that telephone conversations are easy to misinterpret.
Explanation / Answer
a)
Sample Size: 2485
Observed Proportion: 75.45%
Confidence Level: 95%
Confidence Interval:
±1.69
z/2 = 1.9599639861
Lower Bound = p - z/2•p(1 - p)/n = 0.7545 - (1.9599639861)(0.0086336049717863) = 0.7375784452
Upper Bound = p + z/2•p(1 - p)/n = 0.7545 + (1.9599639861)(0.0086336049717863) = 0.7714215548
Confidence Interval = (0.7375784452, 0.7714215548)%
Sample Size: 2485
Observed Proportion: 48.85%
Confidence Level: 95%
z/2 = 1.9599639861
Lower Bound = p - z/2•p(1 - p)/n = 0.4885 - (1.9599639861)(0.010027482356727782) = 0.4688464957
Upper Bound = p + z/2•p(1 - p)/n = 0.4885 + (1.9599639861)(0.010027482356727782) = 0.5081535043
Confidence Interval = (0.4688464957, 0.5081535043)
Related Questions
drjack9650@gmail.com
Navigate
Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.