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standard normal density Using the following curve, determine what is the probabi

ID: 3351132 • Letter: S

Question

standard normal density Using the following curve, determine what is the probability that a random variable z less than 2.12 SELECT ALL APPLICABLE CHOICES 0.98321 -0.32774 0.3 -1.6387 39.328 0.1 0.49160 1.3109 -2.12 G) None of These Use the normal distribution to approximate the desired probability. A coin is tossed 24 times. A person, perception, is asked to predict the outcome of each flip in advance. She predicts correctly on 16 tosses. What is the probability of being correct 16 or more times by guessing? SELECT ALL APPLICABLE CHOICES who claims to have extrasensory 7.852094% 7.902094% 7.652094% 7.402094% E) 7.318761% 7.952094% G) None of These 24 A bank's loan officer rates applicants for credit. The ratings are normally distributed with a mcan of 240.0 and a standard deviation of 48.0 If an applicant is randomly selected, find the probability of a rating that is between 164.0 and 216.0. SELECT ALL APPLICABLE CHOICES B) 21.18648% 25.18648% D) 17.18648% 29.18648% F) None of Thesc 33.18648%

Explanation / Answer

Answer to the question is as follows. In case you don't understand any part of it, please let me know and I will be able to help you out:

22.

From the Z tables we calcualte the value as:

P(Z<2.12) = .98321

A is correct

23.

With the params of binomial distribution we calcualte the probability:

n = 24
x = 16
p=.5 ( its a loss or a win, with equal probability)

P(X=16,n=24,p=.5) = nCx (p^x)(1-p)^n-x = 0.07579 or 7.579%

G. None of these is Correct

24.

With the normal dist params, we will normalize:

Mean = 240
Stdev = 48
P(164<X<216) = P(164-240/48 <Z< 216-240/48) = P(-76/48 <Z< -1/2) = .631-.30854 = .25186478

So, B) 25.18648% is correct