Data from 14 cities were combined for a 20-year period, and the total 280 city-y

Question

Data from 14 cities were combined for a 20-year period, and the total 280 city-years included a total of 140 homicides. After finding the mean number of homicides pen city-year, find the probability that a randomly selected city-year has the following numbers of homicides, then compare the actual results to those expected by using the Poisson probabilities Homicides each city-year Actual results C. 169 86 21 4 a. P(0)- 6036 (Round to four decimal places as needed.) b. P(1)- 3071 (Round to four decimal places as needed.) c. P(2)075 (Round to four decimal places as needed.) d. P(3)- 0143 (Round to four decimal places as needed.) (Round to four decimal places as needed.) The actual results consisted of 169 city-years with 0 homicides; 86 city-years with one homicide; 21 city-years with two homicides; 4 city-years with three homicides; 0 city-years with four homicides. Compare the actual results to those expected by using the Poisson probabilities. Does the Poisson distribution serve as a good tool for predicting the actual results? O O No, the results from the Poisson distribution probabilities do not match the actual results Yes, the results from the Poisson distribution probabilities closely match the actual results

Explanation / Answer

from above:

0.0018

as expected value are airly close to actual value

therefore : Yes the result from poisson distribution probabilities closely match the actual results.

probability(p) homicides actual expected=280*p 0.6065 0 169 170 0.3033 1 86 85 0.0758 2 21 21 0.0126 3 4 4

0.0018

4 0 0 280 280.0

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