MATH 3307 Quiz 2 NAME 1) (5pts) Three married couples have purchased theater tic

Question

MATH 3307 Quiz 2 NAME 1) (5pts) Three married couples have purchased theater tickets and are seated in a row consisting of just six seats. How many different seating arrangements are possible? How many different seating arrangements have Jim and Paula (husband a) TOTAL: b) and wife) seated (in any order) in the two seats on the far left? TOTAL: Assume the theater-goers take their seats in a completely random fashion. Then each of the seating arrangements in part a) are equally likely. Find the probability that Jim and Paula end up seated next to each other in the two seats on the far left. c) PROBABILITY 2) (Spts) A 3-digit number will be formed using the digits 1, 2, 3, 4, 5. Each digit will only once.

Explanation / Answer

1)
a)
number of different seating arrangement = 6! = 720
b)
4 persons beside Paula and jim can be arranged in 4! ways
Jim and Paula can be arranged in 2 ways at far left

hence number of ways = 2 * 4! = 48

c)
probability = 48/720 = 2/30 = 1/15

Related Questions

Navigate

• Browse (All)
• Browse M
• Subjects

---

---

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.