Homework: HmWrk 4.2 Multiplication Rule Save Score: 4 of 6 pts 5of8(8 complete)
ID: 3352593 • Letter: H
Question
Homework: HmWrk 4.2 Multiplication Rule Save Score: 4 of 6 pts 5of8(8 complete) HW Score: 75.51%, 37 of 49 pts 4.2.26 Question Help Hospitals typically require backup generators to provide electricity in the event o a power outage. Assume that emergency backup generators fail 41% of the times when they are needed. A hospital has two backup generators so that power is available if one of them fails during a power outage. Complete parts (a) and (b) below. 0.1681 (Round to four decimal places as needed) b. Find the probability of having a working generator in the event of a power outage. Is that probability high enough for the hospital? Assume the hospital needs both generators to fail loss than 1% of the time when nooded. .8319 (Round to four decimal places as needed.) Is that probability high enough for the hospital? Select the correct answer below and, if necessary, fill in the answer box to complete your choice. O A No, because both generators fail about % of the time they are needed. Given the importance of the hospital's needs, the reliability should be improved. Round to the nearest whole number as needed.) B. Yes, because both generators fail about % of the time they are needed, which is low enough to not impact the health of patients. (Round to the nearest whole number as needed.) C. Yes, because it is impossible for both generators to fail Click to select and enter your answer(s) and then click Check Answer All parts showng Clear All Check AnswerExplanation / Answer
Let A: first generator fails
B: second generator fails
P(A) =41% =0.41
P(B) =41% =0.41
P(both fail) =P(AnB) =P(A)*P(B) (because both are independent generators so,they are independent events)
=0.41*0.41
=0.1681
=17%
so choice B
Yes because both generators fail about 17% of the time they are needed
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