QUESTION 16 6 points Save Answe .Consider the following CD problem from 9.4 and

Question

QUESTION 16 6 points Save Answe .Consider the following CD problem from 9.4 and 9.6 Using traditional methods it takes 106.0 hours to receive a basc dring license. A new license training method usng Computer Alided Instruction (CAD has been proposed. A researcher used the technique on 25 students and observed that they had a mean of 109.0 hours and sample standard deviation is found to be 6.21. Here population standard deviation its unknown. Assume normal distribution, Is there evidence at the 0.05 level that the technique performs above the traditional method? 2 (a is the most important step which helps First Step: Type of Test (Left tail or Right Tail or Two Tail) you to take right decisions) Second Step: TS value Third Step: p-value Fifth Step: Critical Value from table : (round to 3 places) Cerss than 0.0 or noto . Socth Step: Is TS value Step Two more than or less than critical value Conclusion: Reject Ho or Accept Ho 2 points Save Answer

Explanation / Answer

Solution:-

State the hypotheses. The first step is to state the null hypothesis and an alternative hypothesis.

Null hypothesis: < 106.0
Alternative hypothesis: > 106.0

Note that these hypotheses constitute a one-tailed test. The null hypothesis will be rejected if the sample mean is too small.

Formulate an analysis plan. For this analysis, the significance level is 0.05. The test method is a one-sample t-test.

Analyze sample data. Using sample data, we compute the standard error (SE), degrees of freedom (DF), and the t statistic test statistic (t).

SE = s / sqrt(n)

S.E = 1.242
DF = n - 1

D.F = 24
t = (x - ) / SE

t = 2.42

tcritical = 1.71

where s is the standard deviation of the sample, x is the sample mean, is the hypothesized population mean, and n is the sample size.

The observed sample mean produced a t statistic test statistic of 2.42

Thus the P-value in this analysis is 0.012.

Interpret results. Since the P-value (0.012) is less than the significance level (0.05), we have to reject the null hypothesis.

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