A+B only You need not copy the table. For each part an expression like P(E) = 0.
ID: 3354788 • Letter: A
Question
A+B only
You need not copy the table. For each part an expression like P(E) = 0.33 + 0.52 = 0.85 without any discussion is explanation enough.
22. The following two-way contingency table gives the breakdown of the population in a particular * locale according to party affiliation (A, B, C, or None) and opinion on a bond issue: Opinion Affiliation Favors Opposes Undecided 0.12 0.09 0.07 0.16 0.14 0.04 0.03 0.06 None 0.08 0.06 0.03 A person is selected at random. Find the probability of each of the following events. 0.12 a. The person is affiliated with party B. b. The person is affiliated with some party. c. The person is in favor of the bond issue. d. The person has no party affiliation and is undecided about the bond issue.Explanation / Answer
A) P(Person is affiliated with party B) = 0.16 + 0.12 + 0.14 = 0.42
B) P(Person is affiliated with some party) = 1 - P(None party) = 1 - (0.08 + 0.06 + 0.03) = 1 - 0.17 = 0.83
Related Questions
Hire Me For All Your Tutoring Needs
Integrity-first tutoring: clear explanations, guidance, and feedback.
Drop an Email at
drjack9650@gmail.com
drjack9650@gmail.com
Navigate
Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.