This Question: 1 pt 3 of 3 (1 complete) A local car dealership currently has 32

Question

This Question: 1 pt 3 of 3 (1 complete) A local car dealership currently has 32 used Company A, Company B, and Company C vehicles that can be 24 vehicles are cars classified as elther cars or trucks. The following data are available. Complebe parts a) through g) belovw 0 vehicles are Company A 4 vehicles are Company B 2 vehicles are both Company C and trucks 13 vehicles are both Company B and cars a) What is the probability that a randomly selected vehicle is a Company C? (Round to three decimal places as needed) b) What is the probablity that a randomly selected vehicle is a truck (Round tothree domai places as needed.) c) What is the probability that a randomly selected vehicle is ether a Company Bor a car? Round to thee decimal places as needed) d) What is the probability that a randomly selected vehicle is a Company A truck? (Round to tree decimal places as needed ) e)What is the probability that a randomly selected vehicle is a Company C. given t is a ca Pond to tree domal places as reeded ) e, what to probabity that arardomy selected vutid. is a hick, given it aCompany B? 6 caps lock control option command

Explanation / Answer

Car = 24

Total = 32

Therefore Truck = 32 - 24 = 8

P(Car) = 24/32

P(Truck) = 8/32

A) What is the probility that a randomly selected vehicle is a Company C?

P(C)=1 - P(A) - P(B)

= 1-(10/32) - (14/32)

P(C) = 8/32 = 0.25

B) What is the probability that a randomly selected vehicle is a truck?

P(Truck) = 1-P(Car)

= 1-24/32

= 8/32

= 0.25

C) What is the probability that a randomly selected vehicles is either company B or a car?

P(Company B or Car) = P(Compnay B) + P(Car) - P(Company B & Car)

= (14/32) + (24/32) - (13/32)

= 25/32

= 0.7812

D) What is the probability that a randomly selected vehicle is a Company A truck?

P(Comapny B & Car) = 13/32

P(Comapny B & Truck) = 14/32 - 13/32

= 1/32

Truck = 8

Company B & Truck = 1

Company C & Truck = 2

P(Company A & Truck) = (8-1-2)/32

= 5/32

= 0.1562

E) What is the probability that a randomly selected vehicle is Company C, given it is a car?

P(Company C & Truck) = 2/32

P(Company C & Car) = 8/32-2/32

= 6/32

P(Company C | Car) = P(Company C & Car)/P(Car) = (6/32) / (24/32) = 0.25

F) What is the probability that a randomly selected vehicle is a truck, given that it is a Company B?

P(truck | Company B) = P(Company B & truck)/P(Company B) = (1/32) / (14/32) = 0.071429

  

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