a. a. 7 5. For the following set of data, compute the score that defines the 50t

Question

a. a. 7 5. For the following set of data, compute the score that defines the 50th percentile: 94 95, 96, 97, 97, 98, 98, 99, 99, 99, 100, 100. 6. Compute the interquartile range for the 7. What are the two approaches to reporting 8. What is the advantage of standard scores data in Exercise 5 percentiles? What rationale underlies each position? compared with percentile ranks as an index of relative standing? Given a distribution with a mean of 20.00 and a standard deviation of 3.00, compute the standard score equivalents of the fol- owing scores: a. 21.87 c. 18.91 e. 15.63 b. 23.00 d. 20.08 f. 24.30 10. Given a distribution with a mean of-4.00 and a standard deviation of 2.50, compute the standard score equivalents of the fol- lowing scores: a. -6.83 c. 2.84 e. 1.00 b. 0 d. -6.50 f. .87

Explanation / Answer

5. 50th percentile = Median of the data set

Here,

Number of terms = 12 (Even)

Hence,

Median = Average of 6th and 7th term = (98 + 98)/2 = 98

So,

50th percentile = 98

6. Interquartile range = Q3 - Q1

Here,

First quartile = Median of first 6 values = Average of 3th and 4th term = (96 + 97)/2 = 96.5

Third quartile = Median of last 6 values = Average of 9th and 10th term = (99 + 99)/2 = 99

So,

IQR = 99 - 96.5 = 2.5

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