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Edit View History Bookmarks Tools Window Help Do Homework-Christina Holt https://www.mathxl.com/Student/P aspx7homeworkld 44943084 Math 201-007 Busi 230-007 F17 Schweitzer Christina Hon 11/6/175:53 PM Homework: Test 2 Review Assignment Score: 0 of 1 pt 6.3.13 Save 55 of 58(51 complete) MN Score: 79.11%,45.88 of 58 pts Queation Help In a survey of 3178 adults, 1403 say they have started paying bills online in the last year Construct a 99% confidence interval for the population proportion. Interpret the results A99% onfdene iteval tr te population proportion, isOD (Round to three decimal places as needed.) 70 Enter your answer in the edit fields and then click Check Answer

Explanation / Answer

here estimated proportion phat =1403/3178=0.4415

std error =(phat*(1-phat)/n)1/2 =0.0088

for 99% CI ; z =2.5758

therefore 99% confidence interval for population proportion =phat -/+ z*Std errror =0.419 to 0.464

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